diff --git a/datetimes.qmd b/datetimes.qmd
index f272f11..c5ee212 100644
--- a/datetimes.qmd
+++ b/datetimes.qmd
@@ -519,24 +519,27 @@ It's obvious what `dyears(1) / ddays(365)` should return: one, because durations
 What should `years(1) / days(1)` return?
 Well, if the year was 2015 it should return 365, but if it was 2016, it should return 366!
 There's not quite enough information for lubridate to give a single clear answer.
-What it does instead is give an estimate, with a warning:
+What it does instead is give an estimate:
 
 ```{r}
 years(1) / days(1)
 ```
 
 If you want a more accurate measurement, you'll have to use an **interval**.
-An interval is a duration with a starting point: that makes it precise so you can determine exactly how long it is:
+An interval is a pair of starting and ending date times, or you can think of it as a duration with a starting point.
+
+You can create an interval by writing `start %--% end`:
 
 ```{r}
-next_year <- today() + years(1)
-(today() %--% next_year) / ddays(1)
+to_next_year <- today() %--% (today() + years(1))
+to_next_year
 ```
 
-To find out how many periods fall into an interval, you need to use integer division:
+You could then divide it by a duration or a period:
 
 ```{r}
-(today() %--% next_year) %/% days(1)
+to_next_year / ddays(1)
+to_next_year / months(1)
 ```
 
 ### Summary